Close the wizard and perform a system reboot to allow changes to take effect.
CONVERT PPM TO PPMV LICENSE
Read EULA (End User License Agreement) and agree to proceed with the installation process.
CONVERT PPM TO PPMV WINDOWS
Allow Windows to run the file (if necessary). Locate and double-click on the available setup file. Unzip the file and enter the newly-created directory. Save the downloadable package on an accessible location (such as your desktop).
CONVERT PPM TO PPMV INSTALL
To install this package please do the following: Even though other OSes might be compatible as well, we do not recommend applying this release on platforms other than the ones specified. If it has been installed, updating (overwrite-installing) may fix problems, add new functions, or expand existing ones. Of each component multiplied by that components mole fraction, orĭetermine the HV G of a mixture which comprises of N 2,Īnd C 4H 10 with respective mole fractions of 0.0515,Ġ.811, 0.0967, 0.0351, and 0.0056.This package contains the files needed for installing the Audio driver. Gross heating value of a mixture is given the sum of the heating value C p is given as 0.26 Btu/lb-☏.ġ400 lb x 0.26 Btu/lb-☏ x (1000☏-200☏)Įxercise: What would be the heat transferred over a period of one Stream is 1400 lb/min, when the temperature of the gas is raised from 200☏ The amount of heat required to a fluid which undergoes a temperature changeįurthermore, the rate of heat transfer, Q, can be defined:ĭetermine the rate of heat transfer if the mass flow rate of the gas Of the gas is 0.075 lb/ft 3 and the viscosity is 1.16 x 10 -5Ģ.75 x 10 5 > 4000 therefore flow is turbulentĮxercise: At what velocity would the above gas need to achieve Through a 1.7 ft diameter duct at a velocity of 25 ft/sec. It is defined:ĭetermine the Reynolds number and the flow behavior for a gas flowing whether the flow is laminar or transitional. It provides information about the flow behavior of theįluid, i.e. Reynolds Number is the ratio of the inertial forces to viscous forcesĪcting on a fluid. Note : The velocity calculated in the above problem isĮxercise: Determine the stack discharge velocity at 125☏įor a 2.4 ft diameter stack with the same standard exhaust conditions. Rewriting ideal gas law in terms of density,īy combining Boyle's law and Charles law, we get at constant pressure.Ĭalculate crossectional area of the stack. Temperature in C + 273 = Temperature in Kelvin. Temperature in F + 460 = Temperature in Rankine. = 1.986 cal/gmole-K.Ībsolute temperatures ( Rankine or Kelvin) are used in the ideal gas law. The bottom of the column of liquid, with 11 meters high and with a density due to gravity *height of liquid column.Įxercise: Determine the absolute and gauge pressure exerted at Of the column of liquid, with 1m height and with a density of 1200 Kg/m3. Is equal to 101.3 KPa absolute (760mm of mercury or 2116 lbf/ft 2).ĭetermine the pressure, both absolute and gauge, exerted at the bottom The average molecular weight of the mixture.Ītmospheric pressure is the pressure exerted by the atmosphere on the = 32*0.436 + 46*0.455+64 *0.109 = 41.858Įxercise: For a mixture equal weights of O 2 and SO 2,ĭetermine the mole fractions and weight fraction of each component and = (mol.wt of A * mole fraction of A) + (mol.wt ofī * mole fraction of B) + (mol.wt of C * mole fraction of C).Īvg. Weight of all the components in a mixture, if contains 20 lbs of O 2,įind the molecular weight(mol.wt.) of each gas.ĭetermine the number of moles of each gas. Total moles = moles A + moles B + moles C.ĭetermine the mole fraction, weight fraction and average molecular Mole fraction of A = ( Moles of A ) / ( Total moles )
Supposing a mixture has A, B, and C as its components. Of methanol is 0.91 multiplied by density of water = 1 g/cm 3. Weight Fraction, Mole Fraction, and Average Molecularįor example Specific gravity of methanol is given as 0.91. Ppm x molecular weight(g/mol) x 1000 ( mg*L/m 3*g)ġ.5 x 10 4 ppm x 28(g/mol) x 1000 ( mg*L/m 3*g)Įxercise: An exhaust gas containing 3.2 percent by volume SO 2
The exhaust from a 1981 Honda contains 1.5% by volume of carbon monoxide.Ĭompute the concentration of CO in milligrams/m 3 at 25☌ Molecular weight(g/mol) x 1000 ( mL/m 3*g)Įxercise: Carbon Monoxide concentration at 90☌ and 6 atm is Express this concentration in parts per millionĪT STP conditions (25☌ and 1 atm), one mole of gas occupies 24.5 L Introduction to Air Pollution - Workbook A I R PĪn SO 2 concentration is given as 830 mg/m 3Īt 25☌ and 1 atm.